Finding Pythagorean Triples with a Hypotenuse of 85 Using Paper and Pencil
Pythagorean triples are sets of three positive integers (a), (b), and (c) that satisfy the Pythagorean theorem, (a^2 b^2 c^2). If the hypotenuse (c) is 85, finding the corresponding integer values of (a) and (b) can be done using paper and pencil with a series of calculations and checks for perfect squares.
Understanding Pythagorean Triples
Using the Pythagorean theorem, we can find the right triangle sides that form a Pythagorean triple with a hypotenuse of 85. The equation is:
a^2 b^2 85^2
Steps to Find the Pythagorean Triples
1. Calculate the value of (c^2):
   85^2  7225
2. Set up the equation: a^2 b^2 7225
3. Loop through possible values of (a) from 1 to 84 (since (a) must be less than the hypotenuse (c)). For each value of (a), calculate (b^2):
   b^2  7225 - a^2
4. Check if (b^2) is a perfect square. If it is, calculate (b) as the square root of (b^2).
Example Calculations
Here are some example calculations to find the Pythagorean triples:
For (a 7)
b^2  7225 - 7^2  7225 - 49  7176
   7176 is not a perfect square.
For (a 56)
b^2  7225 - 56^2  7225 - 3136  4089
   4089 is not a perfect square.
For (a 60)
b^2  7225 - 60^2  7225 - 3600  3625
   3625 is not a perfect square.
For (a 65)
b^2  7225 - 65^2  7225 - 4225  3000
   3000 is not a perfect square.
For (a 75)
b^2  7225 - 75^2  7225 - 5625  1600
   b  sqrt{1600}  40
   Thus, one Pythagorean triple is 75, 40, 85
For (a 84)
b^2  7225 - 84^2  7225 - 7056  169
   b  sqrt{169}  13
   Thus, another Pythagorean triple is 84, 13, 85
Summary of Pythagorean Triples with Hypotenuse 85
The Pythagorean triples with a hypotenuse of 85 are:
75, 40, 85 84, 13, 85These are the two Pythagorean triples with a hypotenuse of 85.
Alternative Methods
Another approach involves using the properties of Pythagorean triples generated by (m) and (n), where (m) and (n) are positive integers, and m^2 - n^2, 2mn, m^2 n^2 form a Pythagorean triple. If (m 9) and (n 2), then 81 - 4 85, and the triple is 36, 77, 85. If (m 7) and (n 6), then 49 - 36 85, and the triple is 13, 84, 85.
Example Using ((x, y))
Let x be the base and y be the perpendicular of a triangle with hypotenuse 85, then:
85^2 x^2 y^2
85^2 - x^2 y^2
85 - x sqrt{85^2 - x^2}
We need to choose (x) in such a way that it makes the left-hand side a perfect square.
For x 84. Left hand side 1 * 169 13^2
For x 77. Left hand side 8 * 162 16 * 81 36^2
For x 75. Left hand side 10 * 160 1600 40^2
For x 68. Left hand side 17 * 153 17^2 * 3^2 51^2
Therefore, we have the following Pythagorean triples:
85, 84, 13 85, 77, 36 85, 75, 40 85, 68, 51